银行排队叫号系统的毕业论文

#include <>#include <>#define ASK_OP(response) puts("INPUT O = IN Ordinary V = IN VIP Q = QUIT");response = getch();typedef struct _cus{ int no; char type; int type_num; struct _cus *next; }customer; int main(int argc, char *argv[]){ customer * phead = NULL, *pcur = NULL, *ptail = NULL; int i,j; char ch; ASK_OP(ch); while(('Q' != ch) && ('q' != ch)) { if('o' == ch || 'O' == ch) { if(NULL == phead) { if(NULL == (phead = (customer *)malloc(sizeof(customer))))return ; phead->no = 1; phead->type = 'o'; phead->type_num = 0; phead->next = NULL; pcur = phead; } else { i=0; //记录类型为 Ordingary 的个数 ptail = phead; while(!(NULL == ptail->next)) { if(ptail->type == 'o') i = ptail->type_num; ptail = ptail->next; } if(ptail->type == 'o') i = ptail->type_num; if(NULL == (pcur = (customer *)malloc(sizeof(customer)))) return ; ptail->next = pcur; pcur->no = ptail->no+1; pcur->type = 'o'; pcur->type_num = i+1; pcur->next = NULL; } printf("\n%d Ordinary %d 前面有%d人等待\n",pcur->no,pcur->type_num,pcur->no-phead->no); } if('v' == ch || 'V' == ch) { if(NULL == phead) { if(NULL == (phead = (customer *)malloc(sizeof(customer)))) return ; phead->no = 1; phead->type = 'v'; phead->type_num = 0; phead->next = NULL; pcur = phead; } else { i=0; //记录类型为 Vip 的个数 ptail = phead; while(!(NULL == ptail->next)) { if(ptail->type == 'v') i = ptail->type_num; ptail = ptail->next; } if(ptail->type == 'v') i = ptail->type_num; if(NULL == (pcur = (customer *)malloc(sizeof(customer)))) return ; ptail->next = pcur; pcur->no = ptail->no+1; pcur->type = 'v'; pcur->type_num = i+1; pcur->next = NULL; } printf("\n%d VIP %d 前面有%d人等待\n",pcur->no,pcur->type_num,pcur->no-phead->no); } ASK_OP(ch); } printf("\n GOOD bye"); system("PAUSE"); return 0;}

自己多去银行按按号，就了解了...哈哈

啊。。好难的问题。我有朋友卖这个的。以后咱们可以合作啊。你开发个

聚聪科技，百度一下，你就知道。